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[AMR] updated first 4.5 sections

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janishutz committed 2026-08-08 12:31:01 +02:00
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electives/amr/parts/00_basics/00_probability.tex
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@@ -5,7 +5,7 @@
\shorttheorem[Bayes] $\displaystyle \P(Y_i | X) = \frac{\P(X | Y_i) \P(Y_i)}{\sum_{j = 1}^n \P(X | Y_j) \P(Y_j)}$
\shortdefinition[Cont. Var] Sums become integrals\\
\shortdefinition[Cont. Var] Sums become integrals (and vice-versa)\\
e.g. $\sum_{X} \P(X) = 1$ becomes $\int \P(x) \dx = 1$
\shortdefinition[Indep.] $x, y$ indep. iff $\P(\cX \cap \cY) = \P(\cX) \P(\cY)$