[Analysis] Add notes

This commit is contained in:
2026-01-23 13:07:46 +01:00
parent 6f2d107a52
commit fe01067f51
3 changed files with 5 additions and 2 deletions

View File

@@ -67,6 +67,9 @@ Image of par. curve $\gamma: [a, b] \rightarrow \R^n$ is negligible, since $\gam
\rmvspace \rmvspace
\bi{How to compute the integral:} We compute each integral "inside out". For a definite integral, don't just find the anti-derivative, compute the actual integral! \bi{How to compute the integral:} We compute each integral "inside out". For a definite integral, don't just find the anti-derivative, compute the actual integral!
For an integral as seen in the harder example, we compute it as we normally would, simply using the $\pm 2x$ as the $a$ and $b$ For an integral as seen in the harder example, we compute it as we normally would, simply using the $\pm 2x$ as the $a$ and $b$.
Using a change of variables into polar coordinates may come in handy, e.g. for a set like $\{ (x, y) \in \R^2 \divides 1 \leq x^2 + y^2 \leq 4 \}$,
we can use polar coordinates and the integral is then $\int_{0}^{2\pi} \int_{1}^{2} f(x, y) \dx r \dx \varphi$ (or flipped of course)
\rmvspace \rmvspace

View File

@@ -53,4 +53,4 @@ Be cognizant of what direction the integral goes, if the set is on the right han
If the curve doesn't fully enclose the set, then we can simply compute the line integrals of the missing sections and subtract them from the final result. If the curve doesn't fully enclose the set, then we can simply compute the line integrals of the missing sections and subtract them from the final result.
\shade{gray}{Center of mass} \shade{gray}{Center of mass}
% TODO: Finish the notes here The center of mass of an object $\cU$ is given by $\displaystyle \overline{x}_i = \frac{1}{\text{Vol}(\cU)} \int_{\cU} x_i \dx x$.