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[PS] Some fixes
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@@ -14,4 +14,4 @@ Dann $( T := \min\{ n \geq 1 \divider X_n = 1 \} )\sim \text{Geom}(p)$
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\shortremark $T = \8$ ist möglich, $\P[T = \8] = 0$
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\shorttheorem $T \sim \text{Geom}(p)$, dann\\
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$\forall n \geq 0 \; \forall k \geq 1 \; \P[T \geq n + k | T > n] = \P[T \geq k]$
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$\forall n \geq 0 \; \forall k \geq 1 \; \P[T \geq n + k \divider T > n] = \P[T \geq k]$
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