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[Analysis] Add example
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\method \textbf{Educated Guess}\\
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\method \textbf{Educated Guess}\\
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Usually, $y$ has a similar form to $b$:
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Usually, $y$ has a similar form to $b$:
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\begin{tabular}{ll}
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\begin{footnotesize}
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\hline
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\begin{center}
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$b(x)$ & \text{Guess} \\
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\begin{tabular}{ll}
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\hline
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\hline
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$a \cdot e^{\alpha x}$ & $b \cdot e^{\alpha x}$ \\
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$b(x)$ & \text{Guess} \\
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$a \cdot \sin(\beta x)$ & $c\sin(\beta x) + d\cos(\beta x)$\\
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\hline
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$b \cdot \cos(\beta x)$ & $c\sin(\beta x) + d\cos(\beta x)$\\
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$a \cdot e^{\alpha x}$ & $b \cdot e^{\alpha x}$ \\
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$ae^{\alpha x} \cdot \sin(\beta x)$ & $e^{\alpha x}\left(c\sin(\beta x) + d\cos(\beta x)\right)$\\
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$a \cdot \sin(\beta x)$ & $c\sin(\beta x) + d\cos(\beta x)$\\
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$be^{\alpha x} \cdot \cos(\beta x)$ & $e^{\alpha x}\left(c\sin(\beta x) + d\cos(\beta x)\right)$\\
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$b \cdot \cos(\beta x)$ & $c\sin(\beta x) + d\cos(\beta x)$\\
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$P_n(x) \cdot e^{\alpha x}$ & $R_n(x) \cdot e^{\alpha x}$\\
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$ae^{\alpha x} \cdot \sin(\beta x)$ & $e^{\alpha x}\left(c\sin(\beta x) + d\cos(\beta x)\right)$\\
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$P_n(x) \cdot e^{\alpha x}\sin(\beta x)$ & $e^{\alpha x}\left( R_n(x) \sin(\beta x) + S_n(x) \cos(\beta x) \right)$\\
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$be^{\alpha x} \cdot \cos(\beta x)$ & $e^{\alpha x}\left(c\sin(\beta x) + d\cos(\beta x)\right)$\\
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$P_n(x) \cdot e^{\alpha x}\cos(\beta x)$ & $e^{\alpha x}\left( R_n(x) \sin(\beta x) + S_n(x) \cos(\beta x) \right)$\\
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$P_n(x) \cdot e^{\alpha x}$ & $R_n(x) \cdot e^{\alpha x}$\\
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\hline
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$P_n(x) \cdot e^{\alpha x}\sin(\beta x)$ & $e^{\alpha x}\left( R_n(x) \sin(\beta x) + S_n(x) \cos(\beta x) \right)$\\
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\end{tabular}
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$P_n(x) \cdot e^{\alpha x}\cos(\beta x)$ & $e^{\alpha x}\left( R_n(x) \sin(\beta x) + S_n(x) \cos(\beta x) \right)$\\
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\hline
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\end{tabular}
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\end{center}
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\end{footnotesize}
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\remark If $\alpha, \beta$ are roots of $P(X)$ with multiplicity $j$, multiply guess with a $P_j(x)$.
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\remark If $\alpha, \beta$ are roots of $P(X)$ with multiplicity $j$, multiply guess with a $P_j(x)$.
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\subsection{Linear Solutions: Constant Coefficients}
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\subsection{Linear Solutions: Constant Coefficients}
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\textbf{Form:}
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\textbf{Form:} $ y^{(k)} + a_{k-1}y^{(k-1)} + \ldots + a_1y' + a_0y = b$\\
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$$
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y^{(k)} + a_{k-1}y^{(k-1)} + \ldots + a_1y' + a_0y = b
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$$
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\subtext{Where $a_0, \ldots, a_{k-1} \in \C$ are constants, $b(x)$ is continuous.}
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\subtext{Where $a_0, \ldots, a_{k-1} \in \C$ are constants, $b(x)$ is continuous.}
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\subsubsection{Homogeneous Equations}
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\subsubsection{Homogeneous Equations}
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\smalltext{The idea is to find a Basis of $\S$:}
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The idea is to find a Basis of $\S$:
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\definition \textbf{Characteristic Polynomial} $P(X) = \prod_{i=1}^{k} (X-\alpha_i)$
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\definition \textbf{Characteristic Polynomial} $P(X) = \prod_{i=1}^{k} (X-\alpha_i)$
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\end{subbox}
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\end{subbox}
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\subtext{Solutions exist $\forall Z = (z_1,\ldots,z_k)$ since that system's $\det(M_Z) \neq 0$.}
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\subtext{Solutions exist $\forall Z = (z_1,\ldots,z_k)$ since that system's $\det(M_Z) \neq 0$.}
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\newpage
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\subsubsection{Inhomogeneous Equations}
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\subsubsection{Inhomogeneous Equations}
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\method \textbf{Undetermined Coefficients}: An educated guess.
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\method \textbf{Undetermined Coefficients}: An educated guess.
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\remark \textbf{Applying Linearity}\\
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\remark \textbf{Applying Linearity}\\
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If $b(x) = \sum_{i=1}^{n} b_i(x)$, A solution for $b(x)$ is $f(x) = \sum_{i=1}^{n} f_i(x)$\\
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If $b(x) = \sum_{i=1}^{n} b_i(x)$, A solution for $b(x)$ is $f(x) = \sum_{i=1}^{n} f_i(x)$\\
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\subtext{Sometimes called \textit{Superposition Principle} in this context}
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\subtext{Sometimes called \textit{Superposition Principle} in this context.}
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\subsection{Other Methods}
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\subsection{Other Methods}
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\method \textbf{Change of Variable}\\
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\method \textbf{Change of Variable}\\
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If $f(x)$ is replaced by $h(y) = f(g(y))$, then $h$ is a sol. too.\\
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If $f(x)$ is replaced by $h(y) = f(g(y))$, then $h$ is a sol. too.\\
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\subtext{Changes like $h(t) = f(e^t)$ may lead to useful properties.}
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\subtext{Changes like $h(t) = f(e^t)$ may lead to, i.e. ODEs in constant coeffs}
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\begin{footnotesize}
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\textbf{Example:} $2xy' - y = 0$ \\
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Using substitution: $x = e^t,\quad h(t) = y(e^t),\quad h'(t) = e^t \cdot y'(e^t)$
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\begin{enumerate}
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\item $2x \cdot y'(x) = 2 \cdot h'(t)$
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\item $-y(x)$ = $-h(t)$
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\end{enumerate}
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So: $2xy' - y \overset{\text{sub}}{=} 2h'(t) - h(t) = 0$ \\
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Yields: $h(t) = \alpha \cdot e^\frac{t}{2} \overset{\text{resub}}{\implies} y(x) = \alpha \cdot e^\frac{\ln(x)}{2} = \alpha \cdot \sqrt{x}$
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\end{footnotesize}
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\begin{subbox}{Separation of Variables}
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\begin{subbox}{Separation of Variables}
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Form:
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Form:
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@@ -119,15 +129,16 @@ If $f(x)$ is replaced by $h(y) = f(g(y))$, then $h$ is a sol. too.\\
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\subtext{Usually $\int 1/a(y)\ \text{d}y$ can be solved directly for $\ln|a(y)|+c$.}
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\subtext{Usually $\int 1/a(y)\ \text{d}y$ can be solved directly for $\ln|a(y)|+c$.}
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\subsection{Method Overview}
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\subsection{Method Overview}
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\begin{footnotesize}
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\begin{center}
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\begin{center}
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\begin{tabular}{l|l}
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\begin{tabular}{l|l}
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\textbf{Method} & \textbf{Use case} \\
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\textbf{Method} & \textbf{Use case} \\
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\hline
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\hline
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Variation of constants & LDE with $\ord(F)=1$ \\
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Variation of constants & LDE with $\ord(F)=1$ \\
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Characteristic Polynomial & Hom. LDE w/ const. coeff. \\
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Characteristic Polynomial & Hom. LDE w/ const. coeff. \\
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Undetermined Coefficients & Inhom. LDE w/ const. coeff. \\
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Undetermined Coefficients & Inhom. LDE w/ const. coeff. \\
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Separation of Variables & ODE s.t. $y' = a(y)\cdot b(x)$ \\
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Separation of Variables & ODE s.t. $y' = a(y)\cdot b(x)$ \\
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Change of Variables & e.g. $y' = f(ax + by + c)$ \\
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Change of Variables & e.g. $y' = f(ax + by + c)$ \\
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\end{tabular}
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\end{tabular}
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\end{center}
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\end{center}
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\end{footnotesize}
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