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[PS] Fix more errors
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@@ -12,7 +12,7 @@
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\forall A \in \cF \quad \P[A] = \sum_{i = 1}^{n} \P[A | B_i] \cdot \P[B_i]
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\]
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\shorttheorem[Bayes] $B_i$ wie oben, damm $\forall A$ mit $\P[A] > 0$:
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\shorttheorem[Bayes] $B_i$ wie oben, dann $\forall A$ mit $\P[A] > 0$:
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\[
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\forall i = 1, \ldots, n \quad \P[B_i | A] = \frac{\P[A | B_i] \P[B_i]}{\sum_{j = 1}^{n} \P[A | B_j] \P[B_j]}
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\]
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