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[AD] Fixes #2
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@@ -70,7 +70,7 @@ The concept for this algorithm is selecting an element (that being the largest o
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\item \textbf{Efficiency:} Works well for small datasets or nearly sorted arrays.
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\item \textbf{Time Complexity:}
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\begin{itemize}
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\item Best case (already sorted): $\tcl{n\log(n)}$
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\item Best case (already sorted): $\tcl{n}$
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\item Worst case (reversed order): $\tco{n^2}$
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\item Average case: $\tct{n^2}$
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\end{itemize}
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