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[PS] Some fixes
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@@ -3,13 +3,15 @@
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mit $\sigma$ Standardabweichung. Auch: Gauss'sche Verteilung
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mit $\sigma$ Standardabweichung. Auch: Gauss'sche Verteilung
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\shortdefinition[Standardnormalverteilung] $\cX \sim \cN(0, 1)$:\\
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\shortdefinition[Standardnormalverteilung] $\cX \sim \cN(0, 1)$:\\
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$f_\cX = \varphi$ und $\F_\cX = \Phi = \int_{-\8}^{x} \varphi(t) \dx t = \frac{1}{\sqrt{2\phi}} \int_{-\8}^{x} e^\frac{-t^2}{2} \dx t$
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$\Phi = \int_{-\8}^{x} \varphi(t) \dx t = \frac{1}{\sqrt{2\pi}} \int_{-\8}^{x} e^\frac{-t^2}{2} \dx t$ mit $\varphi = f_\cX$.\\
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\bi{Es gilt}: $\Phi(-t) = 1 - \Phi(t)$
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\shorttheorem $cX \sim \cN(\mu, \sigma^2)$, dann $\frac{\cX - \mu}{\sigma} \sim \cN(0, 1)$, also:
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\shorttheorem $\cX \sim \cN(\mu, \sigma^2)$, dann $\frac{\cX - \mu}{\sigma} \sim \cN(0, 1)$, also:
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\[
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\[
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F_\cX(x) = \P[\cX \leq x] = \P\left[ \frac{\cX - \mu}{\sigma} \leq \frac{x - \mu}{\sigma} \right] = \Phi \left( \frac{x - \mu}{\sigma} \right)
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F_\cX(x) = \P[\cX \leq x] = \P\left[ \frac{\cX - \mu}{\sigma} \leq \frac{x - \mu}{\sigma} \right] = \Phi \left( \frac{x - \mu}{\sigma} \right)
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\]
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\]
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\newpage
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\shortexample für Phänomene modellierbar mit Normalverteilung:
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\shortexample für Phänomene modellierbar mit Normalverteilung:
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\begin{itemize}
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\begin{itemize}
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\item Streuung von Messwerten um Mittelwert
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\item Streuung von Messwerten um Mittelwert
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@@ -9,7 +9,7 @@
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\begin{itemize}
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\begin{itemize}
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\item $\cX \sim \cU([a, b])$, $a < b$: $\E[\cX] = \frac{a + b}{2}$
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\item $\cX \sim \cU([a, b])$, $a < b$: $\E[\cX] = \frac{a + b}{2}$
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\item $\cX \sim \text{Exp}(\lambda)$, $\lambda > 0$: $\E[\cX] = \frac{1}{\lambda}$
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\item $\cX \sim \text{Exp}(\lambda)$, $\lambda > 0$: $\E[\cX] = \frac{1}{\lambda}$
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\item $\cX \sim \cU(\mu, \sigma^2)$, $z = x - \mu$, $\dx z = \dx x$: $\E[\cX] = \mu$
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\item $\cX \sim \cN(\mu, \sigma^2)$: $\E[\cX] = \mu$
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\item $\cX \sim \text{Cauchy}(x_0, \gamma)$: Existiert nicht (Int. $\8$)\\
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\item $\cX \sim \text{Cauchy}(x_0, \gamma)$: Existiert nicht (Int. $\8$)\\
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$\E[\cX_+] = \E[\cX_-] = \8$, Median: $0$
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$\E[\cX_+] = \E[\cX_-] = \8$, Median: $0$
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\end{itemize}
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\end{itemize}
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