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[PS] Gausians
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@@ -245,9 +245,38 @@ $$
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\end{enumerate}
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\subtext{(2) wird \textit{Gedächtnislosigkeit} genannt.}
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\newpage
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\definition \textbf{Normalverteilung} $X \sim \mathcal{N}(m, \sigma^2)$
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$$
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f_X(x) = \frac{1}{ \sqrt{2\pi\sigma^2} } e^{ -\frac{(x-m)^2}{2\sigma^2} }
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$$
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\lemma \textbf{Eigenschaften von} $\mathcal{N}$
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\begin{center}
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\includegraphics[width=0.5\linewidth]{res/normal-distribution.png}
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\end{center}
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\lemma \textbf{Summe von Normalverteilten ist normalverteilt}\\
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\smalltext{$X_1,\ldots,X_n$ unabh. s.d. $X_i \sim \mathcal{N}(m_i,\sigma_i^2)$}
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\begin{align*}
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Z &= m_0 + \lambda_1X_1 + \ldots + \lambda_nX_n \\
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Z &\sim \mathcal{N}\Biggl( \underbrace{m_0 + \sum_{i=1}^n \lambda_iX_i}_{m_Z}\quad,\quad \underbrace{\sum_{i=1}^n \lambda_i^2 \sigma_i^2}_{\sigma^2_Z} \Biggr)
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\end{align*}
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\definition \textbf{Standardnormalverteilung}
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$$X \sim \mathcal{N}(0,1) \qquad \Phi(x) := \P[X \leq x]$$
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\lemma \textbf{Symmetrie} $\quad \Phi(-x) = 1-\Phi(x)$
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\lemma \textbf{Normalverteilung via } $\mathcal{N}(0,1)$\\
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\smalltext{$Z \sim \mathcal{N}(m, \sigma^2) \text{ arbiträr},\quad X \sim \mathcal{N}(0,1)$}
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$$
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Z = m + \sigma\cdot X
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$$
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\lemma \textbf{Standardisierung}\\
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\smalltext{$Z \sim \mathcal{N}(m, \rho^2),\quad x\in\R$}
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$$
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\P[x\leq Z] = \Phi\Biggl( \frac{x - m}{\rho} \Biggr)
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$$
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@@ -128,6 +128,15 @@ $$
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\mathbb{V}[X] = \E[X^2]-\E[X]^2
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$$
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{\footnotesize
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\textbf{Beispiel:} Bestimme $\E\bigl[X^2\bigr]$, wobei $X \sim \text{Poisson}(\lambda)$, $\lambda > 0$.
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\begin{align*}
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\V[X] &= \E\bigl[X^2\bigr] - \E[X]^2 & (X \sim \text{Poisson}(\lambda)) \\
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\lambda &= \E\bigl[X^2\bigr] - \lambda^2 \\
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\lambda + \lambda^2 &= \E\bigl[X^2\bigr] \\
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\end{align*}
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}
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\lemma \textbf{Eigenschaften}
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\begin{align*}
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\text{(i)} &\quad \V[X] \geq 0 \\
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