[TI] Compact: Add intuition for reduction ordering

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2025-12-12 10:45:06 +01:00
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@@ -70,6 +70,10 @@ we only need to show that there exists no TM $M$, for which $L(M) \in \cL_{RE}$.
\label{sec:reductions} \label{sec:reductions}
This is the start of the topics that are explicitly part of the endterm. This is the start of the topics that are explicitly part of the endterm.
For the reductions, it is important to get the order right.\\
To show that a language $L_1$ is not part of e.g. $\cL_R$, show that there exists a reduction into a language $L_2 \notin \cL_R$, i.e. e.g. show $L_2 \leq_R L_1$.\\
To show that a language $L_1$ is part of e.g. $\cL_R$, show that there exists a reduction into a language $L_2 \in \cL_R$, i.e. e.g. show $L_1 \leq_R L_2$.
For a language to be in $\cL_R$, in contrast to $L \in \cL_{RE}$, the TM has to halt also for \texttt{no} instances, i.e. it has to be an algorithm. For a language to be in $\cL_R$, in contrast to $L \in \cL_{RE}$, the TM has to halt also for \texttt{no} instances, i.e. it has to be an algorithm.
In other words: A TM $A$ can enumerate all valid strings of a \textit{recursively enumerable language} ($L \in \cL_{RE}$), In other words: A TM $A$ can enumerate all valid strings of a \textit{recursively enumerable language} ($L \in \cL_{RE}$),
where for \textit{recursive languages}, it has to be able to difinitively answer for both \texttt{yes} and \texttt{no} and thus halt in finite time for both. where for \textit{recursive languages}, it has to be able to difinitively answer for both \texttt{yes} and \texttt{no} and thus halt in finite time for both.

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