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[PS] Examples
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@@ -50,7 +50,7 @@ $$
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\definition \textbf{Standardisierung von $S_n$}
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$$
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S_n^* := \frac{S_n - n\mu}{\sigma\sqrt{n}} = \frac{S_n - \E[S_n]}{\sqrt{\V[S_n]}}
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S_n^* := \frac{S_n - n\mu}{\sigma\sqrt{n}} = \frac{S_n - \E[S_n]}{\sqrt{\V[S_n]}} \sim \mathcal{N}(0,1)
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$$
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\subtext{Im Skript auch $Z_n$}
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@@ -58,6 +58,26 @@ $$
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\newpage
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{\footnotesize
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\textbf{Beispiel}: Approximation via Standardisierung mit ZGS.
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Sei $X_i,\ldots,X_n \overset{\text{i.i.d.}}{\sim} \P_X$ s.d. $\forall i: \E[X_i]=8, \V[X_i]=1.44$.
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für $S_{100} = \sum_{i=1}^{n}X_i$ approximieren wir $\P\Bigl[ 788 \leq S_100 \leq 824 \Bigr]$\\
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Es gilt: $\E[S_{100}] = 100\cdot\E[X_i] = 800,\quad \V[S_{100}]=100\cdot\V[X_i] = 144$
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\begin{align*}
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&\P\Bigl[ 788 \leq S_100 \leq 824 \Bigr] \\
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= &\P\Biggl[\frac{788 - \E[S_{100}]}{\sqrt{\V[S_{100}]}} \leq \frac{S_{100} - \E[S_{100}]}{\sqrt{\V[S_{100}]}} \leq \frac{824 - \E[S_{100}]}{\sqrt{\V[S_{100}]}}\Biggr] \\
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= &\P\Bigl[ -1 \leq \frac{S_{100} - \E[S_{100}]}{\sqrt{\V[S_{100}]}} \leq 2 \Bigr] \\
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= & \Phi(2) - \Phi(-1) \\
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= & \Phi(2) - (1-\Phi(1)) \\
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= & \Phi(2) + \Phi(1) - 1 \\
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\approx & 0.8185
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\end{align*}
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Genutztz wurde die Symmetrie von $\Phi$ und $\frac{S_{100} - \E[S_{100}]}{\sqrt{\V[S_{100}]}} \sim \mathcal{N}(0,1)$.\\
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\subtext{Gemäss ZGS Nur eine approximation, da wir hier $n=100$ nutzen.}
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}
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{\footnotesize
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\textbf{Beispiel}: Zentraler Grenzwertsatz als Teststatistik
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