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[Analysis] Add notes on task type
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@@ -34,7 +34,17 @@ This implies that most elementary functions are differentiable.\\
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\compactproposition{Chain Rule} For $X \subseteq \R^n$ and $Y \subseteq \R^m$ both open and $f: X \rightarrow Y$ and $g : Y \rightarrow \R^p$ are both differentiable.
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Then $g \circ f$ is differentiable on $X$ and for any $x \in X$, its differential is given by
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$\dx (g \circ f)(x_0) = \dx g(f(x_0)) \circ \dx f(x_0)$.
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The Jacobi matrix is $J_{g \circ f}(x_0) = J_g(f(x_0)) J_f(x_0)$ (RHS is a matrix product, i.e. multiply rows of first with cols of second matrix)\\
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The Jacobi matrix is $J_{g \circ f}(x_0) = J_g(f(x_0)) J_f(x_0)$ (RHS is a matrix product, i.e. multiply rows of first with cols of second matrix)
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\bi{For tasks} where we are given the value of a gradient at a certain point, as well as the function
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(could not be explicitly given, but could instead be individually for each component),
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we can compute the partial derivative using the chain rule as follows:
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$\frac{\partial g}{\partial \phi} = \frac{\partial g}{\partial x} \cdot \frac{\partial x}{\partial \phi}
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+ \frac{\partial g}{\partial y} \cdot \frac{\partial y}{\partial \phi} + \frac{\partial g}{\partial z} \cdot \frac{\partial z}{\partial \phi}$
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where all $\frac{\partial g}{\partial x}$, etc are known from the gradient and the other elements can be computed quickly from the known equations.
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Finally, evaluate $\frac{\partial g}{\partial \phi}$ at the required points and compute the result.
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% ────────────────────────────────────────────────────────────────────
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\setLabelNumber{all}{11}
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\compactdef{Tangent space} The graph of the affine linear approximation $g(x) = f(x_0) + u(x - x_0)$, or the set
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